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Mathematics Q & A
integration
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shashank
October 2008
integrate
(cos(x))^2/1+a^x
w.r.t x
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admin
October 2008
substitute cosx^2 = (1+cos2x)/2
u will get :
2I = ∫ dx- ∫a^x/1+a^x dx + ∫ cos2x/1+a^x dx
Integrate seperately
For : ∫a^x/1+a^x dx
substitute : 1+a^x = y
and use d/dx (1+a^x) = a^x lna
For : ∫ cos2x/1+a^x dx
Use integration by parts twice . You should get the solution
Do post if you find the suggestions useful or if u face any problems solving it .... Keep Posting
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ankita2
October 2008
hmmm....interesting....but im confused!! hehehe...
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admin
October 2008
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October 2008
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