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Mathematics Q & A
integration
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shashank
November 2008
integrate
x^9/(x^2+4)^6
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Friction
November 2008
Hmmm....
Put x^2 +4 = t
You get :
(t-4)^4/ t^6.....expand and integrate individually .. You will get :
-128/5/(x^2+4)^5+32/(x^2+4)^4+4/(x^2+4)^2-16/(x^2+4)^3-1/2/(x^2+4)
8)
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Mathelp
September 2010
Please check if we take x^2+4 = t, then x^2 = t-4 or, x^8 = (t-4)^4
therefore, x^9 = sqt (t-4) x (t-4)^4.
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Friction
November 2008
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September 2010
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