1st step : count the no. of valence electrons[ V ] 2nd step : now divide V by 8 ,if V >8 or divide V by 2 ,if V <=8 -[1] if the remainder is still not zero then again divide it by 2, - [2] therefore the final value = quotient in 1+ quotient in 2 as shown in the example 3rd step : compare the above obtained value with the table given below :- sp - 2 sp2 - 3 sp3 - 4 sp3d - 5 sp3d2 - 6 sp3d3 - 7 ex:- for c2h6 step 1 - 2[4 ] + 6[1] = 4+6=10 step 2 - as 14>8 14/8, quotient=1 as remainder = 6 which is not equal to zero therefore 6 / 2 quotient=3 therefore final value=1+3=4 comparing with the table given above the hybridisation is sp3. note - this is not applicable to all compounds