chase the dream not the competition

Over 1000+ articles, updated everyday...for Free SMS Alerts click here , Engineering Q&A forum here

Invite Friends
Search:     Advanced Search
Browse by category:
 

Thermodynamics revision sheet for IIT-JEE and AIEEE

Vist the new KnowledgeBin forum to ask all your questions!

KnowledgBin.org SMS Registration

Click Here to Register Online

Creative Commons License
KnowledgeBin.org is licensed under a Creative Commons Attribution-Noncommercial-No Derivative Works 2.5 India License.

Thermodynamics revision sheet for IIT-JEE and AIEEE

 

Temperature
TF=9/5 TC + 32°
TC = TK - 273.15 K
The pressure,volume and temperature in kelvin of such gases obey the equation
PV=nRT ----(1)
Thermal expansion

ΔL=αLΔT


Specific Heat Capacity=ΔQ/mΔT




Gas Laws
Boyles Law: PV=constant
Charles Law : V/T=constant
Dalton Law of Partial Pressure: P=P1 + P2 +P3
Root mean Square Velocity
Vrms=√3RT/M
Mean  Velocity
Vm=√8RT/&#960M
Most Probable Velocity
V=√2RT/M
Also
Vrms > Vm > V

Average kinetic Energy of Gas=3/2nRT

First law of Thermodynamics

ΔU=Q-W


Gas Processes

Isothermal Process : PV=constant ,ΔU=0,Q=W,Molar Specific Heat=infinity
Adaibatic Process : PVy=constant,Q=0,ΔU=-W,Molar Specific Heat=zero
Polytropic Process : PVn=constant,Molar Specific Heat=[R/(y-1) + R/(1-n)]
Volume Constant : P/T=constant W=0,ΔU=Q,Molar Specific Heat=Cv
Pressure Constant : V/T=constant ΔU=Q-W ,Molar Specific Heat=CP

Internal energy depends on Temperature.
So for same temperature change ΔT
nCvΔT=Q1-W1=Q2-W2=Q3-W3

Molar Specfic Heat Capacity of any process is given by

C=Cv + Pdv/ndT where n is no of moles of the gas

Workdone by Gas= ∫PdV

Heat Conduction

Q=-KAdT/dx

Wein displacement lawλT4=Constant

Stefan's Law
Q=eσT4

Newton law of Cooling

dT/dx=b(T-Ts)

 

 

 

Problem Solving tips

1.     Net Heat flow at a junction is Zero

2.     Internal Energy does not depend on the path

3.     Internal Energy in a cyclic  Process is zero

4.     Heat is positive when given to the system and negative when taken out of the system

5.     Workdone by the system on the surrounding is positive while the workdone on the system by the surrounding is megative


 

 

TIP FOR CONVERSION - TEMPERATURE UNITS:

 

LET TEMP IN A SYSTEM (LIKE CELSIUS, KELVIN ETC)   BE  -   T

AND FREEZING POINT OF WATER IN THE SYSTEM BE -  F

AND BOILING POINT OF WATER IN THE SYSTEM BE - B

 

THEN,

 

T - F / B - F  = A CONSTANT

 

ie,  T- 0/ 100 - 0   (in celsius) = T - 32 / 212 -32 (fahrenhiet) = T - 273 / 373 - 273 (kelvin scale)

 

or,   C/100 = (F - 32) / 180 = (K-273)/ 100

Thermodynamics revision sheet for IIT-JEE and AIEEE

SMS Alerts

SocialTwist Tell-a-Friend

Admission Updates

KnowledgeBin Forum Invite Friends

KnowledgeBin Forum Discuss In Forum

Views: 3461
Votes: 2

Others In This Category
document Good Books For IITJEE
document SI Units
document DARK MATTER
document Superconductivity
document Quarks-The Elementary Particle
About Us | Contact Us | Feedback | Copyright © 2008 KnowledgeBin.org™ All rights reserved



RSS