3D Geometry - 2
Illustration: Find angle b/w lines whose direction cosines are &
.
Ans: Let be angle
cos = l1l2 + m1m2 + n1n2
cos = -
= 1200
Straight line:
Vectorial eq. of line:

Let a line passing through a point of P.V.


Then, eq. of line

Proof: Let P be any point on line AP & its P.V. is

Then,





Dumb Question: Why


Ans: Since


So,


Note: Eq. of line through origin & || to



Cartesion eq. of straight line:
Passing through point & parallel to given vector .
Let line is passing through A(x1, y1, z1) & || to EF whose d.r.'s are a, b, c.

d.r.'s of AP = (x - x1, y - y1, z - z1)
d.r.'s of EF = (a, b, c)
Since EF || AP, then,

Illustration: Find eq. of line || to

Ans: A(1, 2, 3)










Vector eq. of line passing through two given points:
Vector eq. of line passing through two points whose P.V. S







Proof:









Cartesian form:
Eq. of line passing through (x1, y1, z1) & (x2, y2, z2)

D.R.'s of AB = (x2 - x1, y2 - y1, z2 - z1)
D.R.'s of AP = (x - x1, y - y1, z - z1)
Since AB || AP

Illustration: Find cartesian eq. of line are 6x + 2 = 3y - 1 = 2z + 2. Find its direction ratios.
Ans:

6x + 2 = 3y - 1 = 2z + 2
6(x +



on comparing a =



Angle b/w Two lines:



Angle b/w two lines cos


If

=


Condition for perpendicularity:



Condition for parallelism:
Dumb Question: Why angle between pair of lines

Ans:



Perpendicular distance of point froma line:
(a) Castesian form:


Suppose 'L' is foot of line of

Since L lies on line AB so,
coordinate of L is


i.e. L(x1 +



direction ratios of PL are:
(x1 +






also direction ratios of AB are (a, b, c)
Since PL








