3D Geometry - 2

Illustration: Find angle b/w lines whose direction cosines are   &   .

Ans:   Let be angle
         cos = l1l2 + m1m2 + n1n2
                
         cos = -   = 1200


Straight line:

Vectorial eq. of line:


Let a line passing through a point of P.V. & || to given line EF().
Then, eq. of line  

Proof: Let P be any point on line AP & its P.V. is
Then, = =   (By law)
        

Dumb Question: Why = ?

Ans: Since is || to EF of P.V.
So, =

Note: Eq. of line through origin & || to is =


Cartesion eq. of straight line:

Passing through point & parallel to given vector .
Let line is passing through A(x1, y1, z1) & || to EF whose d.r.'s are a, b, c.


d.r.'s of AP = (x - x1, y - y1, z - z1)
d.r.'s of EF = (a, b, c)
Since EF || AP, then,
   b Eq. of line in parametric form.


Illustration: Find eq. of line || to & passing through pt.(1, 2, 3) ?

Ans: A(1, 2, 3)   =
eq. of line passing through & || to
    = () + ()


Vector eq. of line passing through two given points:

Vector eq. of line passing through two points whose P.V. S   & is:
     = + ( - )

Proof: is collinear with


  =



Cartesian form:

Eq. of line passing through (x1, y1, z1) & (x2, y2, z2)


D.R.'s of AB = (x2 - x1, y2 - y1, z2 - z1)
D.R.'s of AP = (x - x1, y - y1, z - z1)
Since AB || AP
    


Illustration: Find cartesian eq. of line are  6x + 2 = 3y - 1 = 2z + 2. Find its direction ratios.

Ans:     is cartesion eq. of line
         6x + 2 = 3y - 1 = 2z + 2
         6(x + ) = 3(y - ) = 2(z + 1)
        
         on comparing   a = , b = , c =


Angle b/w Two lines:

    
     =
Angle b/w two lines   cos =
If  
       =
    


Condition for perpendicularity:

     . = 0   a1a2 + b1b2 + c1c2


Condition for parallelism:


Dumb Question: Why angle between pair of lines
      

Ans:     &  
        


Perpendicular distance of point froma line:

(a) Castesian form:


    
Suppose 'L' is foot of line of .
Since L lies on line AB so,
coordinate of L is
     =
i.e. L(x1 + a, y1 + b, z1 + c)
direction ratios of PL are:
     (x1 + a - , y1 + b - , z1 + c - )
also direction ratios of AB are (a, b, c)
Since PL AB
a(x1 + a - ) + b(b - ) + c(z1 + c - ) = 0

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