study material-mathematics-differential calculus
limit-continuity-8
5) Find the point of discontinuity of where .
Solution:
The function is discontinuous at the point x=1 ----- (1)
The function is discontinuous at u=-2 and u=1.
When u = -2,
Hence composite function y = g(x) is discontinuous at three points .
6) If examine the continuity of f(x) at x=1.
Solution:
To examine the continuity at x=1, we are required to derive the definition of f(x) in the intervals x<1, x>1 and at x=1, i.e. on and around x=1.
Now if 0<x<1
So f(x) is not continuous at x=1.
Dumb Question:
1) How does varies with the value of x?
Ans: Now suppose x<1
So,
\ =0
If x =1 then
If x>1 then
7) Show as n® (for n ³ 6)
Solution:
Let while for n ³ 6.
\ By squeeze principle for limits,
.
Ø Limit
Ø Extending / Approaching
Ø Right Hand Limit
Ø Left Hand Limit
Ø Infinity
Ø Sandwitch Theorem / Squeeze play Theorem.
Ø Power Series
Ø L-Hospital’s Rule
Ø Continuity
Ø Removable discontinuity
Ø Irremovable discontinuity