Logarithms - 4

Q10. The value of is greater then 2. true or false ?
Ans:-
                                     =
Now, 12 > 2
So,
or > 2
So, It is true.

Logarithms - flow Questions
Medium
Q1. If a, b, c are distinct positive numbers each different from 1 such that
[logba logca - logaa] + [logab logcb - logbb] + [logac logbc - logcc] = 0 then find the value of abc ?
Ans:- Let us change all logarithms to base
So, the eqn now becomes
= 0 where x = etc.
So, = 3
or, x3 + y3 + z3 - 3xyz = 0
or, (x + y + z)(x2 + y2 + z2 - xy - yz - zx) = 0
Since we have,     x2 + y2 + z2 - xy - yz - zx = [(x - y)2 + (y - z)2 + (z - x)2] 0

** Tip: Writing x2 + y2 + z2 - xy - yz - zx   as [(x - y)2 + (y - z)2 + (z - x)2] which is non-negative for real x, y, z is an useful magnipulation is solving many questions.
So, we calculate x + y + z = 0 that is
= 0
or, = 0
or, abc = 1

Dumb Question:- Why x2 + y2 + z2 - xy - yz - zx is not equal to 0 ?
Ans:- x2 + y2 + z2 - xy - yz - zx = [(x - y)2 + (y - z)2 + (z - x)2]
Now since it is given in question that x, y, z are distinct positive numbers, this cannot be equal to zero.

Q2. If loga(ab) = x, then find value of logb(ab) ?
Ans:- loga(ab) = logaa + logab = 1 + logab = x
So, logab = x - 1
or logba =
or, logba + logbb = + 1
=> logb(ab) =
                   =

Q3. Find the least value of the expression
2 log10x - logx(0.01) for x > 1
Ans:- 2log10x = logx(0.01)
                     = 2 log10 x - logx10-2
                     = 2(log10x + logx10)
                     = 2(log10x + )
                     = 2
                     = 2 + 4
So, the minimum value is 4.








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