Matrices and Determinants for IIT-JEE and AIEEE - Quick Revision
![]() |
If the arrangement has m rows and n columns, then the matrix is of order mxn (read as m by n). |
A matrix is enclosed by a pair of parameters such as ( ) or [ ]. It is denoted by a capital letter. |
![]() |
![]() |
If two matrices A and B are of same order, then A - B = A + (- B). |
![]() |
![]() |
![]() |
![]() |
Suppose A is a matrix of order mxn and B is a matrix of order nxp, the matrix AB is of order mxp. |
![]() |
(a) Matrix multiplication is not commutative, |
i.e., AB ![]() |
(b) Associative law holds good for matrix multiplication, |
i.e., (AB)C = A(BC) |
(c) Matrix multiplication is distributive with respect to addition |
A(B + C) = AB + AC |
or (A + B)C = AC + BC |
![]() |
![]() |
Note that the determinant of kA where k is a scalar and A is a square matrix, is given by kn times determinant of A. |
i.e., is |kA| = kn |A| |
![]() |
![]() |
![]() |
![]() |
![]() |
![]() |
aij = aji |
![]() |
i.e., aij = - aji |
![]() |
![]() |
![]() |
![]() |
![]() |
![]() |
![]() |
Aij = (-1)i+j Mij |
![]() |
![]() |
Adjoint of A is denoted by Adj A. |
Note that the concept of adj is only for square matrix. |
![]() ![]() |
![]() |
![]() ![]() |
In other words, every non-singular matrix is invertible. |
![]() |
![]() |
![]() |
![]() |
using Cramer's rule. |
Step 1: Find the value of the determinant |
![]() |
Step 2: If D ![]() |
![]() |
Where D1, D2 and D3 are the determinants obtained from D by replacing respectively the first column, 2nd column and third column containing the constant terms d1, d2, d3. |
Step 3: If D = 0, the system may have infinite number of solutions or no solution. |
![]() |
![]() |
Step 1: Find the value of the determinants A. That is, find |A| |
Step 2: If |A| = 0, inverse of the matrix A does not exists. |
Step 3: If |A| ![]() |
Step 4: Find adj A, the transpose of the matrix of co-factors Aij. |
Step 5: |
![]() |
![]() |
Let the given system of equations be |
![]() |
Step 1: |
![]() |
The system of linear equations may be expressed as AX = B. |
Step 2: Find |A|. If |A| ![]() |
Step 3: |
If |A| = 0, put x = k (y = k or z = k) in any two of the given equations and find y and z in terms of k. |
Substitute these values of x, y and z in terms of k in the third equation. If the third equation is satisfied by these values of x, y and z, then the system has infinitely many solutions. |
If the third equation is not satisfied, the system has no solution. |