Dumb question - Q. How . P(A/B
1) =
?
And - B
1 Letter from AGRA
So, in AGRA there are 3 two letter consecutive word AG, Ga, RA
and A
RA is legible
So, there is only one 'RA'
P(A / B
1) =
Hard level
Q. 1 Aline of length L is divided (broken ) in to there parts randomly . Find the chance that these parts are the possible sides of
Ans- For to be sides of
,
x > o, y > o
L > X + y
Sum of two sides .> third side
x + y > L -(x + y)
(x + y) >
.........................(1)
L - x > X
=>
...................(2)
L - y > y
..................(3)
n(s)
x L x L =
(from eqn. L > x + y)
n(A) = Area of
ABC
x
x
=
x
P( E )=
=
=
Q. 2 A box contains 6 balls. It is equally likcly that ball is white or black . Two balls are drawn from this bag one is foond black and one is whit.
find the chance that there is 3 black ball in the box .
Ans . 1
st ball can be white of black = 2 way
2
nd ball can be white of black = 2 way
img ............Total no. of ways in which 6 balls can be white of black
= 2 X 2 X 2 X 2 X 2 X 2 = 2
6 ways
n(s) = 2
6
P(B
o) =
, P(B
1) =
P(B
2) =
, P(B
3)
P(B
4)
, P(B
5)
P(B
6) =
A
Two balls drawn from bag & of diff. color
P(A / B
0) = o [b/c in draw of 2 balls one black ball is there]
P(A / B
1) =
P(A / B
2) =
P(A / B
3) =
P(A / B
4) =
P(A / B
5) =
P(A / B
6) = 0
P(A) = P(B
o) P(A / B
o) + P(B
1) P(A / B
1) + P(B
2) P(A / B
2) + P(B
3) P(A / B
3) + P(B
4) P(A / B
4) + P(B
5) P(A / B
5) + P(B
6) P(A / B
6)
=
+
+
P(B
3/ A) =
=
=
P(B
3 / A) =
